When the object reaches the ground, the height is zero, so:
0 = 144 - 16t^2
then you just solve for t, so subtract the 144 over
-144 = -16t^2
then divide by the -16
9 = t^2
then take the square root of both sides
3 = t
therefore, it will take three seconds for the object to reach the ground.
The value of X is 39 degrees. You have to add 102 degrees and 39 degrees to get 141 degrees. All triangles equal up to 180, so subtract 141 from 180, and you get 39 degrees.
2x^2 + 3xy - 4y^2 when x = 2 and y = -4
= 2(2)^2 + 3(2)(-4) - 4(-4)^2 = 2(4) + (-24) - 4(16) = 8 - 24 - 64 = -80
Answer:
Q = -6
Step-by-step explanation:
To find the answer to this, you first must multiply the first function by 2:
2 x (x - 3y = 4)
2x - 6y = 8
Which then means that the second function is the same. This means that to find Q you need to find the number that changed +Qy into -6:
2x - 6y = 8
2x + Qy = 8
The 2x's cancel out, and then remove the equals and the 8:
-6y = Qy
<h3>So Q must be -6</h3>
<h2>Hope this helps!</h2>
10 is not a perfect square I believe
