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Oliga [24]
3 years ago
15

The double number line shows that 5 pounds of avocados cost $9.

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0

Answer:

$1.8

Step-by-step explanation:

Given :

5 pounds of avocado = $9

This means that 5 pounds of avocado cost $9; The cost of 1 pound of Avocado can be obtained thus ;

Let cost of 1 pound of avocado = a

5 pounds = $9

1 pound = a

Cross multiply

5 * a = $9 * 1

5a = 9

Divide both sides by 5

5a / 5 = 9/5

a = 1.8

Hence, 1 pound of avocado will cost $1.8

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What are the factors of -16 ?
RoseWind [281]

Answer:

-1,16 -2/8 -4/4 and the negatives on the other side. I hope that helps

Step-by-step explanation:

3 0
3 years ago
PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Artyom0805 [142]

Answer:

Your second answer, otherwise know as 1 in. : 4ft. is the answer.

Step-by-step explanation:

The new map is 3 times bigger than the old map, therefore your given scale for the first map will shrink by 3 to compensate for the new map being bigger. Divide 12ft by 3 and you get 4 ft., so your answer is 1in. : 4ft.

4 0
3 years ago
Find the length of a rectangular lot with a perimeter of 120 meters if the length is 6 meters more than the width
Vladimir79 [104]

Answer:

The length is 33 and the Width is 27.

Step-by-step explanation:

So I made it easier by only looking at half of the rectangle. 120 divided by 2 is 60. So out of the length and width, it had to add to equal 60. I plugged in a few numbers and determined 27 and 33. SO, if you add those together it equals 60 while 33 is 6 more meters than 27 and two 27 and two 33 equals 120 for the whole rectangle

5 0
3 years ago
For this problem, assume that three students are chosen from 5 freshmen, 4 sophomores, and 4 juniors.
Sati [7]

The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.


<span>The sample space S in our problem is as follows: </span>

triples selected from 5 freshmen, 4 sophomores, and 4 juniors, so that at least 1 freshman is selected.

The selection of 1 freshman can be done in 5 ways. The selection of the remaining 2 out of 4 freshmen (one is already chosen), 4 sophomores, and 4 juniors can be done in C(12, 2) many ways.

C(12, 2)=\displaystyle{  \frac{12!}{2!10!}= \frac{12\cdot11\cdot10!}{2!10!}=66

So there are in total, 5*66= 330 possible triples.

n(S)=330


The event E "selecting 2 freshmen and 1 junior" can occur in :

C(5, 2)\cdot 4=\displaystyle{ \frac{5!}{2!3!}\cdot4=40 many ways.


so n(E)=40


P(E)=n(E)/n(S)=40/330=0.12



Answer: 0.12


 

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20-%286-4x%29" id="TexFormula1" title="\sf -(6-4x)" alt="\sf -(6-4x)" align="absmiddle"
Margaret [11]

Answer:

- (6 - 4x) =  - 6 + 4x

8 0
3 years ago
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