Question 1
Because the period is 2π, and the amplitude is 1obtain
f(x) = sin(x)
Because the horizontal shift is π, obtain
f(x) = sin(x - π)
Because the vertical shift is -4, obtain
f(x) = sin(x - π) - 4
Answer: 1. f(x) = sin(x - π) - 4
Question 2
The radius is 36/2 = 18 in.
1 revolution (360°) is the circumference, which is
2π(18) = 36π in
When the revolution is 62°, the distance traveled is
(62/360)*(36π) = (31/5)π in
Answer: 3. (31π)/5
Question 3.
Consider f(x) = 3cos(2x-π) - 1
f(0) = 3cos(-π) - 1 = -4
f(π/2) = 3cos(0) - 1 = 2
Rate of change = (2+4)/(π/2) = 12/π
From the graph, the rate of change of g(x) is
3/(π/2) = 6/π
Consider h(x) = sin(x) - 4
h(0) = 0 - 4 = -4
h(π/2) = 1 - 4 = -3
Rate of change = (-3+4)/(π/2) = 2/π
Therefore h(x) has the smallest rate of change
Answer: h(x)
The formula of the future value of annuity ordinary is
Fv=pmt [(1+r/k)^(kn)-1)÷(r/k)]
Fv future value?
PMT payment 6200
r interest rate 0.06
K compounded semiannual 2
N time 5 years
Fv=6,200×(((1+0.06÷2)^(2×5)) ÷(0.06÷2))=277,742.72
Hope it helps
Answer:
80°
Step-by-step explanation:
176 - 32 = 144
144(4/9) = 80°
the answer is 80°
