Answer:
The probability that none of the 10 calls result in a reservation is 0.60%. In turn, the probability that at least one call results in a reservation being made is 99.40%.
Step-by-step explanation:
Since approximately 40% of the calls to an airline reservation phone line result in a reservation being made, supposing an operator handles 10 calls, to determine what is the probability that none of the 10 calls result in a reservation, and what is the probability that at least one call results in a reservation being made, the following calculations must be performed:
0.6 ^ 10 = X
0.006 = X
0.006 x 100 = 0.60%
Therefore, the probability that none of the 10 calls result in a reservation is 0.60%.
100 - 0.60 = 99.40
In turn, the probability that at least one call results in a reservation being made is 99.40%.
Answer:
N = 4
Step-by-step explanation:
In the equation 2n + 7 = 15, we have to isolate the variable. But, before that, we have to get rid of anything else. Like the +7 in the equation. So we can subtract from each side.
2n + 7 = 15
Take out the +7 by subtracting 7 on both sides.
2n + 7 - 7 = 15 - 7
2n = 8
Now, to get rid of the 2 next to the n, we have to divide both sides by 2
2n/2 = 8/2
n=4
Answer:
B. (-2, 15)
Step-by-step explanation:
Pretend that your fixed point [2, 9] is at the origin for now by translating it two units <em>west</em><em> </em>then nine units <em>south</em><em> </em>[0, 0]. Now, the same goes for [6, 3]. Translate it two units <em>west</em> then nine units <em>south</em><em> </em>to get [4, -6]. Then, according to the <em>180°-rotation rule</em>, you take the OPPOSITE of both the x-coordinate and y-coordinate:
[4, -6] → [-4, 6]
Now, that you have your rotated point, we have to shift EVERYTHING BACK to the way it was from when we shifted the fixed point of [2, 9] to the origin. We do that by translating everything in reverse order, which is 9 blocks <em>north</em><em> </em>then 2 blocks <em>east</em>:
→ [0, 0] back to [2, 9]
Translation
→ [-4, 6] to the new coordinate of [-2, 15]
I am joyous to assist you anytime.
