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Lerok [7]
3 years ago
11

1 and ⅝ as a percent​

Mathematics
1 answer:
bixtya [17]3 years ago
4 0
162.5 % convert the fraction to a decimal, then multiply by 100.
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Estimate the sum of 202 and 57.
aalyn [17]
The estimate of the sum of 202 and 57 is 260. You add the numbers together and than round up.
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Find the sum of the interior angles of a convex hexagon?
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720

Step-by-step explanation:

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Answer ASAP for BRAINLIEST (NO LINKS OR I REPORT)
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radius = 3 feet

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V = 1/3πr²h

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Show the work and answer for 5550÷10 to the third power
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8 0
3 years ago
A: {71,73,79,83,87} B:{57,59,61,67}
Jobisdone [24]

Answer:

\frac{3}{5}.

Step-by-step explanation:

We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.

We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.

So there are 4 prime number in set A and total numbers are 5.

P(\text{Prime number from A})=\frac{4}{5}

We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.

So there are 3 prime number in set B and total numbers are 4.

P(\text{Prime number from B})=\frac{3}{4}

Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.

P(\text{Prime number from A and B})=\frac{4}{5}\times \frac{3}{4}

P(\text{Prime number from A and B})=\frac{1}{5}\times \frac{3}{1}

P(\text{Prime number from A and B})=\frac{3}{5}

Therefore, the probability that both numbers are prime would be \frac{3}{5}.

4 0
3 years ago
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