The area of a square is 150 square inches. the length of its side is between which two values?

John has decided to prepare an old field for his son's new horse. the length of the field is 10 meters less than 4 times its wid

tatuchka [14]

Answer: The total money invested in the field will be $1,623.80

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

p=2(x+y)

p(4.80)=1,584

p=330m

we know that

The perimeter of the field is equal to

so

330=2(x+y)----> equation A

x=4y-10 ------> equation B

substitute equation B in equation A and solve for y

330=2(4y-10+y)

165=(5y-10)

5y=165+10

y+35

Find the value of x

x=4(35)-10+130

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

A=xy

substitute

A=(130)(35)=4,550m2

step 3

Find the number of bags of seed

Divide the area by 460

4,550/460=9.89 bags

Round up to the nearest whole number

9.89 bags=10 bags

step 4

Find the cost of the seed

(10 )(3.98)=$19.8

step 5

Find the total money invested in the field

1,584+$39.8=$1,623.80

7 0

2 years ago

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2. Devin is holding a skating party, The rental of the ice is $75, plus S3 Dex karex. Devi has

nasty-shy [4]

Answer:

43

Step-by-step explanation:

204-75=129

129/3=43

8 0

2 years ago

Which set of ordered pairs does not represent a function

Alex Ar [27]

<h3>Answer:</h3>

The Second one {(-8,-7), (4,-2), (2,9), (-8,8)}

<h3 /><h3>Step-by-step explanation:</h3>

A function only gives ONE out put for a given value. But the second set has two outputs if we input -8, it gives you -7 and 8 so this must not be a function.

6 0

2 years ago

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What is the value of -2(x+5)?

bezimeni [28]

I thinks 5 because -2(x) = -2x and -2(5)=-10
So -2x=-10
-10/-2=5
X=5

7 0

3 years ago

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Analyze the asymptotes of the function.

koban [17]

Answer:

vertical asymptote at x=-1

horizontal asymptote at y=0

Step-by-step explanation:

$y=\frac{1}{x+1}$

To find vertical asymptote we set the denominator =0 and solve for x

x+1=0 (subtract 1 from both sides)

x=-1

So, vertical asymptote at x=-1

To find horizontal asymptote we look at the degree of both numerator and denominator

there is no variable at the numerator , so degree of numerator =0

degree of denominator =1

When the degree of numerator is less than the degree of denominator

then horizontal asymptote at y=0

5 0

3 years ago