The perimeter of a triangle is the sum of all side lengths of the triangle. The numerical expression for the perimeter of Stephanie's triangle is: 
Let the sides of Juan's triangle be x, y and z. So:

The perimeter (J) of Juan's triangle is calculated by adding all sides.
So:

This gives:


From the question, we understand that:
The perimeter (S) of Stephanie's triangle is half that of Juan.
This means that:

Substitute 25 for J

Hence, the numerical expression for the perimeter of Stephanie's triangle is: 
Read more about perimeters at:
brainly.com/question/11957651
0.0307 or what are you giving us here?
Given:
The two functions are:


To find:
The value of
.
Solution:
We have,


We know that,


![(h\circ g)(b)=[(5b-9)-1]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B%285b-9%29-1%5D%5E2)
![(h\circ g)(b)=[5b-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B5b-10%5D%5E2)
Putting
, we get
![(h\circ g)(-6)=[5(-6)-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B5%28-6%29-10%5D%5E2)
![(h\circ g)(-6)=[-39-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-39-10%5D%5E2)
![(h\circ g)(-6)=[-49]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-49%5D%5E2)

Therefore, the value of
is 2401.
Since this is an obtuse triangle, Point O is not equidistant from A, B, and C. Point O is not on the perpendicular bisectors, so the third statement is true. Point O is equidistant from AB, BC, and CA because these lines are pressed against the circpe in a mannered way.