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3 years ago

Given the following code:

1 answer:

Elena-2011 [213]3 years ago

7 0

Let's go through step by step, starting from inside the while loop.

Is i > 0? Yes. Continue.

ITERATION 1:
i now equals 10 (100 / 10)
j now equals 1 (1 + 10 % 5)

Is i > 0? Yes. Continue.

ITERATION 2:
i now equals 10 (10 / 1)
j now equals 0 (1 + 1 % 5)

Is i > 0? Yes. Continue.

ITERATION 3:
i = i / j; now generates a DivideByZeroException, thus we get a run-time error.<span />

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Write a python program that will read a number (num) and display all the numbers divisible by 3 or 5

coldgirl [10]

DIVISIBLE BY 10

Explanation:

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3 years ago

I have been trying to work on this for a while now, and this is on excel

cluponka [151]

Answer:

=IF(INDEX(INDIRECT(C10), B10)=0,"",INDEX(INDIRECT(C10), B10))

=IF((INDEX((INDIRECT(Dept,TRUE)),Reason))="","",(INDEX((INDIRECT(Dept,TRUE)),Reason)))

Explanation:

Given

Your formula:.

=INDEX(INDIRECT("Dept"),Reason)

Dept column = C (C10)

Reason field = B (B10)

The issue with your formula is that you failed to include a statement to test the falsity of the first condition; in other words, if your if statement is not true, what else should the formula do.

The question says that

"Nest the function inside an IF function so that issues currently displaying as a 0 will display as a blank cell" this means that

if the INDEX() function returns 0, a blank should be displayed in H10 blank, instead.

So, the right formula both of these two. You can use any of them

1. =IF(INDEX(INDIRECT(C10), B10)=0,"",INDEX(INDIRECT(C10), B10))

2. =IF((INDEX((INDIRECT(Dept,TRUE)),Reason))="","",(INDEX((INDIRECT(Dept,TRUE)),Reason)))

The two does the same function; the only difference is that

(1) considers the cell itself while (2) considers the contents of the cell.

The analysis of both is that

They both use a nested indirect reference to check for the content of cells displaying 0.

The first if checks for the above mentioned; if yes, cell H10 is made to display a blank else it's original content is displayed.

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sleet_krkn [62]

Answer:

Print.. is your answer...

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3 years ago

Write a program that (a) generates a vector with 20 random integer elements with integers between -29 and 30, (b) replaces all t

Ghella [55]

Answer:

import random

randomlist = []

for i in range(0,20):

n = random.randint(-29,30)

if n < 0 :

n = 100

randomlist.append(n)

print(randomlist)

Explanation:

The random module is first imported as it takes care of random. Number generation.

An empty list called randomliay is created to hold the generated random integers.

Using a for loop, we specify the range of random numbers we want.

Inside the for loop ; we attach our generated random integer which will be in the range (-29 to 30) in a variable n

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3 years ago