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olga2289 [7]
3 years ago
10

I need help with 19-25. PLEASE NEED ASAP!!

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0

Answer:

That's just -6

Step-by-step explanation:

The 19 is smaller then the 25 so you gotta go back to the negatives, so do 25 - 19 but add a negative.

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Twenty-nine percent of americans say they are confident that passenger trips to the moon will occur in their lifetime. You rando
galina1969 [7]

Answer:

The probability is 0.0014

Step-by-step explanation:

When we have two possible outcomes p, q and we repeat the experiment multiple times, we apply the Binomial distribution, in this distribution the probability of getting exactly k successes in n trials is given by

P(X=k)  = nCk(p)^k(1-p)^{n-k}

where p represents the probability of success. nCk refers to the combinations of k elements out of n elements.

In this case, p= .29 (the probability that the person says "yes" being confident that passenger trips to the moon will occur in their lifetime.

q = .71 (The probability that the person says "no")

We sample 200 americans, therefore, we have n = 200 and we need the probability that less than 40% of the people sampled answer "yes".

The 40% of 200 is 80. So, in other words, we need less than 80 people to answer yes to the question.

P(x<80) = P(x=0) + P(x=1) + P(x=2) + .... + P(x=79) = 0.00143466294 (we can use a Binomial Distribution calculator to compute this result)

Therefore, P(x < 80) = 0.0014

8 0
4 years ago
Jesse and Peyton were on scooters jesse traveled 15 in 6 seconds peyton travels 22 meters in 10 seconds who was moving faster? e
DiKsa [7]

9514 1404 393

Answer:

  Jesse

Step-by-step explanation:

Jesse's distance in 60 seconds would be ...

  (60 s)(15 m)/(6 s) = 150 m

Peyton's distance in 60 seconds would be ...

  (60 s)(22 m)/(10 s) = 132 m

Jesse travels farther in the same amount of time, so Jesse is moving faster.

__

You might find it simpler just to compute the rate of each.

  Jesse: (15 m)/(6 s) = 2.5 m/s

  Peyton: (22 m)/(10 s) = 2.2 m/s

Jesse's speed is higher.

4 0
3 years ago
Rachel has an 80:1 scale drawing of the floor plan of her house. On the floor plan, the dimensions of her rectangular living roo
Allushta [10]

Answer:

208⅓ ft²

Step-by-step explanation:

The dimensions of Rachel's living room are 80 times the measurements on the scale drawing.

Calculate the width:

                                                                                     w = 80 × 1⅞

Convert the mixed number to an improper fraction     = 80 × 15/8

Cancel the 8s                                                                  = 10 × 15

                                                                                        = 150 in

Convert inches to feet                                                   = 150/12  

Convert the improper fraction to a mixed number      = (144 + 6)/12

                                                                                        = 12⁶/₁₂

Reduce the fraction to lowest terms                             = 12½ ft

Calculate the length

l = 80 × 2½  = 80 × 5/2 = 40 × 5 = 200 in = 200/12 = (192 + 8)/12

l = 16⁸/₁₂ = 16⅔ ft

Calculate the area

A = lw

A = 16⅔ × 12½

Convert the mixed numbers to improper fractions

A = 50/3× 25/2

Cancel the 2s

= 25/3 × 25

Multiply numerators and denominators                        

= 625/3

Convert the improper fraction to a mixed number    

= (624 + 1)/3

= 208⅓ ft²

The area of Rachel's living room is 208⅓ ft².

3 0
3 years ago
Find b, given that a = 20, angle A = 30°, and angle B = 45° in triangle ABC
Kamila [148]
<span>The side b is opposite to the angle B, applying the law of the sines, we have:

</span>\frac{a}{sinA} = \frac{b}{sinB}
\frac{20}{sin30^0} = \frac{b}{sin45^0}
\frac{20}{ \frac{1}{2} } = \frac{b}{ \frac{ \sqrt{2} }{2} }
20* \frac{ \sqrt{2} }{2}  = b* \frac{1}{2}
\frac{20 \sqrt{2} }{2} = \frac{b}{2}
2*b =2*20 \sqrt{2}
2b = 40 \sqrt{2}
b =  \frac{40 \sqrt{2} }{2}
\boxed{b = 20 \sqrt{2} }
6 0
3 years ago
Read 2 more answers
Paul has completed 140 laps so far this season. He completes an additional 12 laps during each practice. Jacklyn has completed 5
kakasveta [241]

Paul: 140 + 12x

Jacklyn: 56 + 16x

Where x is how many practice sessions he had this season

"After how many more practices will Paul and Jacklyn have completed the same number of laps?"

This means what will x be if both equations are equal to each other

140 + 12x = 56 + 16x

Isolate x in one side by subtracting both sides by 12x

140 + 12x - 12x = 56 + 16x - 12x

140 = 56 + 4x

Subtract both sides by 56 to shift the 56 from the right side to the left side

140 - 56 = 56 - 56 + 4x

84 = 4x

Divide both sides by 4 to isolate x

84/4 = 4/4x

21 = x

x = 21

They'll have completed the same number of laps after 21 practices

Hope it helps :)

Branliest would be appreciated

6 0
3 years ago
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