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4 years ago

What is the product 7 × 106?

Mathematics

2 answers:

Klio2033 [76]4 years ago

6 0

Answer:

The answer would be 742

levacccp [35]4 years ago

3 0

Answer:

742

Step-by-step explanation:

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3-4y=-1 solve equation

Gwar [14]

Answer:

3-4y=-1

-4y=-4

y=1

4 0

4 years ago

A town has a population of 8000 and grows at 3% every year. To the nearest tenth of a year, how long will it be until the popula

Alexxx [7]

Answer:

It will take approximately 34 years

Step-by-step explanation:

If a town population is 8000 and grows 3% annually.

How long will it take to reach 16300

growth is 16300 - 8000 = 8300

using simple interest formula

SI = (P × r × t)/100

8300 = (8000 × 3 × t)100

8300= (80 × 3)t

8300 = 240t

t = 8300/240

t ≈ 34 years to the nearest tenth

8 0

3 years ago

Hi . The main problem most students have is converting learned material in to ----------------- memory and understanding it .

Sergio039 [100]

Is this a question that we can answer? like mathematically? or was this an accident but i do agree with that!

7 0

3 years ago

A halyard 22 ft long is cut into two pieces. If L is the length of one piece, express the length of the second piece in terms of

tensa zangetsu [6.8K]

Check the picture below

6 0

3 years ago

Practice simplifying rational expressions with negative exponents.

Gelneren [198K]

Answer:

Part 1:- option first is correct

$-\frac{1}{2}ab^{12}$

Part 1:- option third is correct

$\frac{w^{10}}{3y^{4}}$

Step-by-step explanation:

Given:

The given ration expressions are.

1. $\frac{-2a^{2}b^{4}}{4ab^{-8}}$

2. $\frac{-5w^{4}y^{-2}}{-15w^{-6}y^{2}}$

We need to simplify the given expressions.

Solution:

Part 1:-

Given expression is

$=\frac{-2a^{2}b^{4}}{4ab^{-8}}$

Using law of exponents $\frac{x^{m} }{x^{n} } = x^{(m-n)}$

$=-\frac{a^{2-1}b^{4-(-8)}}{2}$

$=-\frac{a^{1}b^{4+8}}{2}$

$=-\frac{ab^{12}}{2}$

$=-\frac{1}{2}ab^{12}$

Therefore, option first $-\frac{1}{2}ab^{12}$ is correct.

Part 2:-

Given expression is.

$=\frac{-5w^{4}y^{-2}}{-15w^{-6}y^{2}}$

Using law of exponents $\frac{x^{m} }{x^{n} } = x^{(m-n)}$

$=\frac{w^{4-(-6)}y^{-2-2}}{3}$

$=\frac{w^{4+6}y^{-4}}{3}$

$=\frac{w^{10}y^{-4}}{3}$

$=\frac{w^{10}}{3y^{4}}$

Therefore, third option $\frac{w^{10}}{3y^{4}}$ is correct.

4 0

3 years ago