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Sonbull [250]
3 years ago
8

I need help on Part B

Mathematics
1 answer:
kirill [66]3 years ago
4 0
Since 90 divided by 5 equals 15 and if u multiply 15 by 4 equals 60. So at the rate that she's working it's gonna take her 4 hours to make $60.
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5x-2=3x+8 must find what X is equal to
serious [3.7K]
I had homework on this today lol

First, add 2 to both sides. It would then be 5x = 3x + 10. Then subtract 3x from both sides and you would end up with 2x = 10. Divide 2x by 2 and the 10 by 2. The answer is x = 5.
6 0
3 years ago
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Sarawong had some candy to give to his four children. He first took nine pieces for himself and then evenly divided the rest amo
svet-max [94.6K]
9+3+3+3=21 or you could do 4*3+9

5 0
3 years ago
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Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from
Lapatulllka [165]
<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units</h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and      y_3=8

The area of a triangle is= \frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]

=|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|

=|-54| = 54 square units

The length of AC = \sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}

                          = \sqrt{(2-12)^{2} +(1-8)^2}

                         =\sqrt{149} units

Let the perpendicular distance from B to AC be = x

According To Problem

\frac{1}{2} \times  x \times \sqrt{149} = 54

⇔x =\frac{108}{\sqrt{149} } units

Therefore the perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units

5 0
3 years ago
Choose one of the factors of x3 − 1331.
Dmitry [639]
Answer A) x-11
Hope this helps!
3 0
3 years ago
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Answer asap please will mark as brainlist
Leona [35]

Answer:

Exact Form:

√ 30

Decimal Form:

5.47722557 …

Step-by-step explanation: i would go with D

6 0
3 years ago
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