Plz help it’s due tomorrow

Find the missing information. <br><br> PLEASE HELP ITS A QUIZ DUE SOON

xxTIMURxx [149]

Answer:

x = 13

∠F = 28°

∠S = 28°

y = 9

DE = 38 ft

Step-by-step explanation:

We are told that △DEF = △QRS

Looking at both triangles and by comparison, it is clear that;

∠R = ∠E = 123°

∠Q = ∠D = 29°

∠S = ∠F = 180 - (123 + 29) = 28°

Also,QR = DE

Thus; 5y - 7 = 38

5y = 38 + 7

5y = 45

y = 45/5

y = 9

Thus,y = 9 and DE = 38 ft

We see in the image that ∠S = (2x + 2)°

From earlier we deduced that ∠S = 28°

Thus; 2x + 2 = 28

2x = 28 - 2

2x = 26

x = 26/2

x = 13

7 0

2 years ago

A line segment on a number line has its endpoints at -9 and 6. Find the coordinate of the midpoint of the segment.. . A. 1.5. *

Lyrx [107]

By definition, the midpoint is given by:
$m = (\frac{x1+x2}{2}, \frac{y1+y2}{2})$

Part A:
For the line segment we have:
$m = \frac{-9+6}{2}$
$m= \frac{-3}{2}$
$m = -1.5$
Answer:
the coordinate of the midpoint of the segment is:
B. -1.5

Part B:
For line segment HX we have:
$m = (\frac{-1+7}{2}, \frac{3-1}{2})$
$m = (\frac{6}{2}, \frac{2}{2})$
$m = (3,1)$
Answer:
the coordinates of the midpoint of the segment is:
A. (3,1)

4 0

2 years ago

Read 2 more answers

How to find how long it will take a rocket to reach a maximum height

Anton [14]

Answer:

the rocket will reach its maximum height after 4 seconds.

Step-by-step explanation:

The first term ( -4.9(t-4)^2 ) can never be positive, so the maximum height of 80 meters is achieved when t = 4.

5 0

2 years ago

A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra

VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that $N = 6$

4 blue, which means that $k = 4$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4$

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that $N = 6$

2 yellow, which means that $k = 2$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667$

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that $P(A) = 0.4 + 0.0667 = 0.4667$

Probability of both being the same color and blue:

40% probability that both are blue, which means that $P(A \cap B) = 0.4$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571$

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0

2 years ago

Help me do this i will pick brailest if right and it is 45 points!

sweet-ann [11.9K]

Answer:

8/21

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers