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Shtirlitz [24]
3 years ago
12

osha requires a ladder to meet the ground at 75 degree angle in order to function as safely as possible. of you need the ladder

to reach a ledge 20 feet up a vertical wall, how long does the ladder need to be?
Mathematics
1 answer:
VMariaS [17]3 years ago
8 0
Draw a right triangle with a right angle and a 75 deg angle at the bottom.
The hypotenuse is the length of the ladder.

sin A = opp/hyp

sin 75 = 20/hyp

hyp = 20/sin 75 = 20.7

Answer: 20.7 ft
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Need help with this question, thank you in advance!
blondinia [14]

Answer:

arc RP = 84 degrees

Step-by-step explanation:

If the angle NPQ is 102 degrees, we can find the angle NPM:

NPM + NPQ = 180

NPM + 102 = 180

NPM = 78 degrees.

Now, with the triangle NPM, we can find the angle MNP:

60 + 78 + MNP = 180

MNP = 180 - 60 - 78 = 42 degrees

The angle MNP is inscribed in the circle, and is related to the arc RP:

arc RP = 2 * MNP

arc RP = 2 * 42 = 84 degrees

3 0
3 years ago
4/5 of a number is 16. What is the number?
Zepler [3.9K]

Answer:

20

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do you subtract 42 minutes from 1 hour 25 minutes? explain what to do and why to do it.
ikadub [295]

Answer:

43

Step-by-step explanation:

you change the 1 hour into minute you and 60min to 25 minutes and then you subtract from 42 minutes to get the solution

8 0
3 years ago
Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x
Natali [406]

Answer: hello your question is incomplete attached below is the complete question

answer :

a)   \int\limits^3_0 {(10-x)-(x+4)} \, dx     ( option D )

b) A =  1/2 (6)(3)   ( option B )

c) Area of shaded region = 9

Step-by-step explanation:

<u>a) Using integration with respect to x </u>

Area =   \int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy         ( note a = 10 )

          = y^2/2 - 4y |⁷₄  + 10y - y^2/2 |¹⁰₇

          = 33/2 - 12 + 30 - 51/2   = 9

hence the best integral from the options attached is option D

\int\limits^3_0 {(10-x)-(x+4)} \, dx

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

= 30 - 9/2 - 9/2 - 12  = 9

<u>b) Using Geometry </u>

Area = 1/2 * base * height

        = 1/2 * 6 * 3

        = 9

7 0
3 years ago
A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa
tatuchka [14]

Answer:

Second puck travels farther

Step-by-step explanation:

Maximum height of first puck = 3 feet

The height of a second hockey puck is modeled by:

y=x\left(0.15-0.001x\right)

y=0.15x-0.001x^2

To find maximum height of second puck

y'=0.15-0.002x

Equate the derivative equals to 0

0.15-0.002x=0

\frac{0.15}{0.002}=x

75 = x

At x = 75

y=0.15(75)-0.001(75)^2=5.625

So, The maximum height of second puck is greater than  first puck

So, Second puck travels farther

5 0
2 years ago
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