Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
I think it is D 1.8. hope this help's
<span>Line ET is tangent to circle A at T
</span>
∴ ET ⊥ TN
∴ ∠ ETN = 90
<span>the measure of Arc TG = 70
</span>
∠ TNG = half <span>the measure of Arc TG = 0.5 *70 = 35
</span>
<span>Δ ETN ⇒ The sum of all angles = 180
</span>
<span>∴∠ GET = ∠ NET = 180 - (90 + 35 ) = 55
</span>
∴ The correct answer is option <span>A. 55°</span>
This is how you find the equation for the line
