Answer:
The ratio of the drag coefficients
is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model,
= The drag coefficient of the prototype, 
The medium of the test for the model,
= The medium of the test for the prototype, 
The drag force is given as follows;

We have;

Therefore;







= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients
≈ 0.0002.
Answer:
9:3 or 9 to 3
Step-by-step explanation:
M = - 1
- 2 = - 1 ( 2 ) + c
- 2 = - 2 + c
c = 0
y = - x
The <u>second image</u> in the diagram is a hyperbola. As can be seen, the plane cutting the cone can be at any angle but never equal to the slant angle of the cone. This has a very important implication. The plane cuts both cones of the double-napped cone. The third double-napped cone of Figure 3 shows two hyperbolas.
Answer:
a) 1.3652
b) 1.3906
Step-by-step explanation:
a) log5 9 = log5 3² = 2log5 3 = 2(0.6826) = 1.3652
b) log5 75/8 = log5 75 - log5 8 = log5 3×25 - log5 8=
log5 3 + log5 5² - log5 8 = 0.6826 + 2 - 1.2920 = 0.6826 + 0.708 = 1.3906