15.9 / 100 = c / 25,250....15.9 c sections to 100 women = c to 25,250 women
cross multiply
(100)(c) = (15.9)(25,250)
100c = 401475
c = 401475/100
c = 4014.75 <===
Answer:
x>6
Step-by-step explanation:
hopefully the answer is clear and understandable.
:)
Rewrite the limand as
(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = (1 - sin(<em>x</em>)) / (cos²(<em>x</em>) / sin²(<em>x</em>))
… = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / cos²(<em>x</em>)
Recall the Pythagorean identity,
sin²(<em>x</em>) + cos²(<em>x</em>) = 1
Then
(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / (1 - sin²(<em>x</em>))
Factorize the denominator; it's a difference of squares, so
1 - sin²(<em>x</em>) = (1 - sin(<em>x</em>)) (1 + sin(<em>x</em>))
Cancel the common factor of 1 - sin(<em>x</em>) in the numerator and denominator:
(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = sin²(<em>x</em>) / (1 + sin(<em>x</em>))
Now the limand is continuous at <em>x</em> = <em>π</em>/2, so
Answer:
a) 1 tsp.
b) 1.5 tsp.
c) 2 tsp.
Step-by-step explanation:
Complete Correct Question
Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog
- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
Solution
a) 18 kg adult dog
The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
9 kg dog weight = (1/2) tsp
18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.
b) 6 kg cat
The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
1 kg cat = (1/4) tsp
6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.
c) 18 kg pregnant dog
The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
4.5 kg dog weight = (1/2) tsp
18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.
Hope this Helps!!!
