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3 years ago

14

Mrs Moore’s and Mrs. Ruiz’s classes are competing for the best scores on their math test. Use the box plots below to answer ques

tions 7-8

2 answers:

maksim [4K]3 years ago

5 0

Sorry , idk how to answer that

Elan Coil [88]3 years ago

3 0

Answer:

Where are the box plots?? I need it to answer the question.

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nydimaria [60]

76 82 87 93 95 98

Mean -
76+82+87+93+95+98 = 531
531/6 = 88.5

Range -
98 - 76 = 22

Median -
Because there are 6 numbers you have to find the average of the middle two
87+93 = 180
180/2 = 90

Mode -
No number is repeated so there is no mode.

8 0

3 years ago

Read 2 more answers

Which table accurately describes the points shown on the following graph?

k0ka [10]

A is the correct answer i'm pretty sure

4 0

3 years ago

Read 2 more answers

Steve had 484848 chocolates but decided to give 888 chocolates to each of his fff coworkers.

katrin2010 [14]

Answer:

483960

Step-by-step explanation:

484848

- 888

______

483960

7 0

3 years ago

Which shows the best estimate to use<br> to find 43 × 78?

bulgar [2K]

Answer:

The best estimate for 43x78 is 40x80

Step-by-step explanation:

43 rounded to the nearest ten is 40.

78 rounded to the nearest ten is 80.

The answer to 40x80 is 3200

7 0

3 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago