Question

If a 2.2-kg ball is thrown with a velocity of 10m/s what is its KE​

Answer 1

Answer:

110 joules

Step-by-step explanation:

$Mass = 2.2kg\\Velocity = 10m/s \\K.E = \frac{1}{2} mv^2\\K.E = \frac{1}{2} \times 2.2 \times 10^2\\K.E = \frac{1}{2} \times 220\\K.E = \frac{220}{2} \\K.E = 110 joules$

Answer 2

Answer:

The answer is 110 Joules

Step-by-step explanation:

Kinetic energy ( KE) of an object is given by

$KE = \frac{1}{2} m {v}^{2}$

where

m is the mass

v is the velocity

From the question

m = 2.2 kg

v = 10 m/s

Substitute these values into the above formula

That's

$KE = \frac{1}{2} \times 2.2 \times {10}^{2}$

$KE = 1.1 \times 10$

We have the final answer as

Kinetic energy = 110 Joules

Hope this helps you