Which is the equation of a hyperbola centered at the origin with x-intercepts +3, and asymptote y = 2X?
1 answer:
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<u>Given</u>:
The sum of 5 consecutive integers is 110.
Let the sequence be x, x + 1, x + 2, x + 3, x + 4
We need to determine the fourth number in the sequence.
<u>Value of x:</u>
Since, the sum of 5 consecutive integers is 110.
Thus, we have;
Adding the like terms, we have;
Thus, the value of x is 20.
<u>Fourth term:</u>
The fourth term of the sequence is x + 3
Substituting x = 20 in the term, we get;
Fourth term = 20 + 3 = 23
Thus, the fourth term of the sequence is 23.
Answer:
radius r = 47/π in
length l = 23.5 in
Step-by-step explanation:
Let us recall that:
Volume of a cylinder = --- (1)
The girth g = ----- (2)
Given that:
height (h) + girth (g) = 141
Then g = 141 - h ----- (3)
Equating equation (2) and (3), we have:
141 - h = 2πr + h
2h = 141 - 2πr
h = 70.5 - πr ------ (4)
From, here now, we can now replace the value of h into equation (1)
i.e.
V = πr²(70.5 - πr)
V = 70.5πr² - π²r³
Taking the differential of the above equation with respect to r, we have:
By further differentiation:
Let set , Then:
141πr - 3π²r² = 0
141πr = 3π²r²
Divide both sides by πr
141 = 3πr
r = 141/3π
r = 47/π in
Replacing the value of r = 47/π into equation (4), we have:
h = 70.5 - πr
h = 70.5 - π(47/π)
h = 70.5 - 47
h = 23.5 in
From equation (3);
h + g = 141
23.5 + g = 141
g = 141 - 23.5
g = 117.5 in
Volume = πr²h
V = π × (47/π )² × 23.5
V = 16523.94 in³