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Vesna [10]
4 years ago
5

What is the domain of this function p(w) 2/3w^9 ...?

Mathematics
1 answer:
Pavlova-9 [17]4 years ago
7 0

You have a fractions, so the only thing you must be sure of is that the denominator is not zero.

In your case, the denominator is given by the function <span><span>f<span>(w)</span></span>=3<span>w9</span></span>. You need to find out the values of w for which <span><span>f<span>(w)</span></span>=0</span>. You have
<span><span>f<span>(w)</span></span>=0⇔3<span>w9</span>=0⇔<span>w9</span>=0⇔w<span>=9</span><span>√0</span>=0</span>

So, your only problem is <span>w=0</span>, and all other numbers are fine.

Your domain is thus given by the set <span>{x∈R∣x≠0}</span>

The domain can also be written as <span><span>(−∞,0)</span>∪<span>(0,+∞)</span></span>.

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3 years ago
The temperature falls from 0 degrees to Negative 12 and one-fourth degrees in 3 and one-half hours. Which expression finds the c
ANEK [815]

Answer:

The expression used to find the change in temperature per hour is Algebraic expression

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

Step-by-step explanation:

A temperature falls from 0 to  - 12\dfrac{1}{4}     in     3\dfrac{1}{2} \ hours

Which expression finds the change in temperature per hour.

From the above given information;

The initial temperature is 0

The final temperature is  - 12\dfrac{1}{4}  

The change in temperature is \Delta T = T_2  -  T_1

\Delta  T = -12\dfrac{1}{4} -0

\Delta T = -12.25

Thus;

-12.25 ° = 3.5 hours

To find the change in x°   per hour; we have;

x°            = 1 hour

The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

(- 12.25° × 1 hour) = (x° × 3.5 hour)

Divide both sides by 3.5 hours; we have:

\dfrac{-12.25^0*1 }{3.5}=\dfrac{ x^0 *3.5}{3.5}

x° =  - 3.5

x° = - 3\dfrac{1}{2}

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

There is no enough evidence to reject the claim using a level of significance of 5%

Step-by-step explanation:

Let p be the true proportion of homeowners in Omaha who own a lawnmower. We want to test  

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We have a large sample of size n = 500 and a point estimate for p is \hat{p}=0.68. The test statistic is given by

Z=\frac{\hat{p}-p_{0}}{\sqrt{p_{0}(1-p_{0})/n}}=\frac{0.68-0.65}{\sqrt{0.65(1-0.65)/500}} where \sqrt{0.65(1-0.65)/500} is the standard error of \hat{p} when H_{0} is true. The observed value is z_{0} = 1.4064 which comes from a standard normal distribution. Because we want to use a level of significance of 5%, our rejection region is RR={z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles respectively. Because 1.4064 does not belong to RR, we fail to reject the null hypothesis.

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A newborn infant is 19.5 inches long. What is her length in centimeters (cm)?
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