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Alexus [3.1K]
3 years ago
9

Show work plz

Mathematics
1 answer:
NemiM [27]3 years ago
6 0
25 percent is the same as the decimal 0.25.

Multiply 100 by 0.25 to see what 25% of 100 is.
100x0.25=25

Then, to find the price raised by 25%, add 25 to 100.
100+25=125

The final answer is $125.

Hope this helps!
You might be interested in
which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

6 0
3 years ago
REALLY NEED HELP:  The Venn Diagram shows a universe with 26 elements and two different outcomes: B and Y
Goshia [24]

Answer:

P(B|Y)=0.4

Step-by-step explanation:

We are given with a Venn diagram of a universe with 26 elements and two different outcomes: B and Y

And we are asked to find P(B|Y)

The formula for P(B|Y)= \frac{P(B\cap Y)}{P(Y)}

From Venn diagram, P(B\cap Y)=\frac{n(B\cap Y)}{26} =\frac{8}{26} =\frac{4}{13}

And P(Y)=\frac{n(Y)}{26}=\frac{8+12}{26}= \frac{20}{26}= \frac{10}{13}

Hence P(B|Y)=\frac{(\frac{4}{13})}{\frac{10}{13}} =\frac{4}{10}=0.4

6 0
3 years ago
Read 2 more answers
Homework help please I'll give you 10 points and brainliest
DaniilM [7]

Answer:

c)

Step-by-step explanation:

Use 49 instead of 14 for 7²

Reason: 7² = 7 * 7 = 49

Not 14 as 7*2 = 14

6 0
2 years ago
Given that , the _____ justifies the conclusion that ∆ABD ≅ ∆AEC.
trasher [3.6K]
AAS Postulate

It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.

Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate. 

Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!

3 0
3 years ago
Read 2 more answers
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
2 years ago
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