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3 years ago

What are the slope and the y-intercept of the linear function that is represented by the equation Y=-10x+1?

Mathematics

2 answers:

dangina [55]3 years ago

8 0

Answer:

b. The slope is -10, and the y-intercept is 1.

Step-by-step explanation:

Y = slope(x) + y-intercept

Rasek [7]3 years ago

3 0

Answer: B) slope = -10, y intercept = 1

The general form is y = mx+b

m = slope

b = y intercept

Comparing y = -10x+1 to y = mx+b we see that

m = -10

b = 1

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Four times the larger of two consecutive even integers is ten less than the smaller. What is the larger of these two numbers?

anygoal [31]

Answer:

-4 is the larger integer

Step-by-step explanation:

n = smaller integer

n + 2 = larger integer

4(n+2) = n-10

4n + 8 = n - 10

3n + 8 = -10

3n = -18

n = -6

n+2 = -4

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2 years ago

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mezya [45]

Answer:

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3 years ago

3x – y = 4 2x + y = 6 (2, 2) (3, 0) (–1, –7) (0, –4)

Vitek1552 [10]

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2 years ago

Read 2 more answers

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.