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lesya [120]
4 years ago
11

How do you write 2.375 x 10^-7 in standard form? (10 to the power of -7) PLEASE HELP!

Mathematics
1 answer:
slava [35]4 years ago
6 0
0000002375 is the answer
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A square has an area of 64 square meters.
34kurt

Answer:

Side is 8 meters, Perimeter is 32 meters

Step-by-step explanation:

<em>One side </em>

Squares have 4 equal sides.  Area is found using l*w, but the sides are all equal in squares. Therefore, the area can be found using:

a=s^2

We know the area is 64, so we can substitute that in

64=s^2

Take the square root of both sides

\sqrt{64}=\sqrt{s^2}

8=s

One side is 8 meters

<em>Perimeter</em>

Squares have 4 equal sides, and the perimeter is all the sides added up.

p=s+s+s+s

We know the side is 8, so we can substitute that in

p=8+8+8+8

p=4*8

p= 32

The perimeter is 32 meters

8 0
3 years ago
6 students share 4 bagels equally
babunello [35]
They would each get one and a half bagels because 6/4= 1.5
3 0
4 years ago
6m + 17  is greater then or equal to 77 (HELP WILL GIVE BRAINLIST)
emmasim [6.3K]

6m> 60

m>10

m is greater than or equal to 10

6 0
2 years ago
Read 2 more answers
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Keisha is separating 656 boxes of cereal
tatuchka [14]
And whats the rest of the question
8 0
3 years ago
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