The gradient of the perpendicular line would be the negative reciprocal of the original line. Therefore the gradient of the perpendicular line would be -2/5x.
Since we know y=mx+c, ∴y=-2/5x+c. Sub in the x and y values of the given point and we get that c=26/5.
The perpendicular equation would be y=-2/5x+26/5.
I hope I got this right.
Answer:
$9261
$1261
Step-by-step explanation:
Principal: $8000
Interest rate: 5% PA compounded annually
Time: 3 years
- Sum = $8000*(1.05)³ = $9261
- Interest = $9261 - $8000 = $1261
A(n) = -5 + 6(n - 1)a(n)=−5+6(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 5, plus, 6, left parenthesis, n, min
DENIUS [597]
Answer:
The 12th term is 61
Step-by-step explanation:
I will assume that your a(n) = -5 + 6(n - 1) is correct; the rest is redundant (duplicative, unneeded).
To find the 12th term, substitute 12 for n in the above formula:
a(12) = -5 + 6(12 - 1) = -5 + 6(11) = 66 - 5, or 61
The 12th term is 61
Answer:
X =
-
Step-by-step explanation:
Answer:
Step-by-step explanation:
M=9-R is the equation for it