Given:
Northern Florida: 2,000 patients ; 64% experienced flulike symptoms during December
Southern Florida: 3,000 patients ; 54% experienced flulike symptoms during December
Standard error = √[p(1-p)/n]
NF = √[0.64(1-0.64)/2000] = √[(0.64*0.36)/2000] = 0.0107 or 1.07%
SF = <span>√[0.54(1-0.54)/3000] = √[(0.54*0.46)/3000] = 0.0091 or 0.91%
smallest margin of error for a 95% confidence interval
NF: Em </span>≈ 0.98/√2,000 = 0.98/44.72 = 0.0219 or 2.19%
<span>SF: Em </span>≈ 0.98/√3,000 = 0.98/54.77 = 0.0178 or 1.78%
<span>
MY ANSWER:
</span><span>B.The southern Florida study with a margin of error of 1.8%.</span>
Answer:
d. 5
Step-by-step explanation:
it just is trust me
Answer:
580 is the answer i thik its helps u tqq
It would be 5/8 i'm pretty sure sorry if it's not right.
The picture shows the answer
HOPE THIS HELPS!!
