What is the 17th term in the arithmetic sequence in which a6 is 101 and a9 is 83
1 answer:
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Looking at the problem, you can come up with an equation for the consecutive numbers.
If we expand the second term:
Combine like terms:
You can reduce this by dividing both sides of the equation by two:
And we transpose 170 to get a standard quadratic form that the right side will be zero:
Then factor the left side:
Find out the values of x that makes each factor = 0
x + 14 = 0
x = -14
We can eliminate the negative symbol because the problem is asking for positive even integers.
and;
x - 12 = 0
x = 12
Now we can say that the first positive integer is 12 and the second one is 14
If we expand the second term:
Combine like terms:
You can reduce this by dividing both sides of the equation by two:
And we transpose 170 to get a standard quadratic form that the right side will be zero:
Then factor the left side:
Find out the values of x that makes each factor = 0
x + 14 = 0
x = -14
We can eliminate the negative symbol because the problem is asking for positive even integers.
and;
x - 12 = 0
x = 12
Now we can say that the first positive integer is 12 and the second one is 14