Alex has 2 1/2 pounds of strawberries and wants to put them in bags weighing 1/3 lb each . How many bags will he have ?

HELP ME PLSS !!!!!!!!!!!!!!!

FrozenT [24]

Answer:

x<8

Step-by-step explanation:

Had that same question

3 0

2 years ago

Read 2 more answers

Fred invests $12,993 into an account that yields 5.59% interest annually. how much interest will Fred have earned after 16 years

daser333 [38]

Answer:

Fred would have earned $31,022.31 after 16 years.

Step-by-step explanation:

To calculate compound interest, the initial capital must be multiplied by the interest rate applied to the capital, and in turn, this number must be exponential by the number of years that the investment lasts. Thus, in the case, the equation would be the following:

12.993 x (1 + 0.0559) ^ 16

In this way, multiplying the result exponentially by 16 years, the final compound interest would be $ 31,022.31.

5 0

3 years ago

What is the answer...............

Harrizon [31]

Answer:

lana

Step-by-step explanation:

she saves 100$ in 2weeks more than 94

6 0

3 years ago

Simplify 7-(x^2-3x+2)-2x(3x^2-x+1)

NeTakaya

Answer:

-6x^3+x^2+x+5

Step-by-step explanation:

distribute (multiply) the 7- into the first set of parenthesis. then distribute (multiply) the -2x into the second set of parenthesis.

3 0

3 years ago

When 3010 adults were surveyed in a poll, 27% said that they use the Internet. Is it okay for a newspaper reporter to write th

tamaranim1 [39]

Answer:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

z=2.53

pv=0.0114

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=3010 represent the random sample taken

X represent the people who says that said that they use the Internet.

$\hat p=\frac{X}{106}=0.27$ estimated proportion of people who says that said that they use the Internet.

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 50% of people who says that they would watch one of the television shows.:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.27 -0.25}{\sqrt{\frac{0.25(1-0.25)}{3010}}}=2.53$

4) Statistical decision

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

We have the significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.53)=2*(0.0057)=0.0114$

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

3 0

3 years ago