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zimovet [89]
3 years ago
14

A company has a main office and 12 branch offices. The users and computers are within a single domain. All servers are Windows S

erver 2016. The administrator must make sure that all data is encrypted by using end-to-end encryption. In addition, instead of using user names and passwords, he needs to use computer-level authentication? What should he do?
Computers and Technology
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

The answer to this question can be given as:

To access the server, the administrator must Configure L2TP with IPsec and MS-CHAPv2.

Explanation:

In this question, the user doesn't access the server by the User name and password. The User wants to access the server by the computer-level authentication. To access the server successfully user must Configure L2TP with IPsec and MS-CHAPv2. where L2TP with IPsec stands for Layer 2 Tunneling Protocol or it is also known as Virtual private network. It is a communications protocol that allows us to move data from one network to another in the encrypted form that is used by the IPsec. MS-CHAPv2 stands for Microsoft Challenge-Handshake Authentication Protocol that is developed by Microsoft. In computing, the CHAP provides the authentication to the user or network host entity. For example, this entity may be an internet service provider. And v2 stands for security.

So to access the server successfully, the administrator must Configure L2TP with IPsec and MS-CHAPv2.

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The code:

filename = input("> ")

with open(filename, "r") as file:

   items = file.read()

   items = items.split("\n")

   for index, item in enumerate(items):

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   for item in items:

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Explenation:

1. We make the user enter the file's path, in our case "food.txt". This does only work if the .txt file is in the <u>same</u> directory as our code.

2. We get the content of our .txt file with the "open" function. If we use the "open" function inside of a "with" statement we don't have to deal with closing the file after we opened it. The file will close as soon as we exit the statement. The argument "r" indicates that we only want to read the file, not do anything else with it.

3. However the variable "file" doesn't contain the <u>contents</u> of "food.txt", only the class object of our file (if you try "print(file)" you'll only get nonsense). We can simply get the content of the file by calling ".read()" after.

4. We can separate this long str using the ".split()" function. The split function seperates a string by another sertain string (in our case "\n", since the different items are seperated by a newline). Now "items" is a list of strings.

5. Next we go through all items in "items" and separate them by "\t", again using the ".split()" function. Enumerate makes a list of indexes and values from another list (in our case, "items").

6. Now we have a list of lists of strings. The only thing left to do is go through every item and print it if the item's third item is equal to "Available" (notice that this is case-sensative). And print out the result in the desired format.

The code works for me, please ask me if there is anything you don't understand (or if the code is incorrect). Happy to help :D

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