Answer:
9. 66°
10. 44°
11. 
12. 
13. 27.3
14. 33.9
15. 22°
16. 24°
Step-by-step explanation:
9. Add 120 + 80 (equals 200) and subtract that from 360 (Because all angles in a quadrilteral add to 360°), this equals 160. Plug the same number in for both variables in the two other angle equations until the two angles add to 160. For shown work on #9, write:
120 + 80 = 200
360 - 200 = 160
12(5) + 6 = 66°
19(5) - 1 = 94°
94 + 66 = 160
10. Because the two sides are marked as congruent, the two angles are as well. This means the unlabeled angle is also 68°. The interior angles of a triangle always add to 180°, so add 68+68 (equals 136) and subtract that from 180, this equals 44. For shown work on #10, write:
68 x 2 = 136
180 - 136 = 44
11. Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #10, write:
a² + b² = c²
a² + 6² = 8²
a² + 36 = 64
a² = 28
a = 
a = 
12. (Same steps as #11) Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #11, write:
a² + b² = c²
a² + 2² = 4²
a² + 4 = 16
a² = 12
a = 
a = 
13. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #13, write:
Sin(47°) = 
x = 27.3
14. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #14, write:
Tan(62°) = 
x = 33.9
15. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #15, write:
cos(θ) = 52/56
θ = cos^-1 (0.93)
θ = 22°
16. (Same steps as #15) Use SOH CAH TOA and solve with a scientific calculator. For shown work on #16, write:
sin(θ) = 4/10
θ = sin^-1 (0.4)
θ = 24°
Good luck!!
Answer:
Step-by-step explanation:
<h2><u>Part A</u></h2>
in interval ( 0 ; 2)
<h2><u>Part B</u></h2>
in interval (2; 4)
<h2><u>Part C</u></h2>
in interval (4 ; 6 )
<h2><u>Part D</u></h2>
The graph shows that at first the ball rises up ; and then it is seen that it goes down and loses height to zero , from which it can be concluded that the height after 10 seconds remains unchanged and therefore the height of the ball after 16 seconds will be zero
Answer:
4/3
Step-by-step explanation:
To know this, let's write down the formulas for the volume of cylinder and sphere.
Vs = 4/3πr³ (1)
Vc = π r² h (2)
Now, we do have a little problem here and its the fact that the sphere do not have a height like the cylinder do. But in this case so if you want to have an idea of the fraction of the volume, we will assume that the cylinder has the same height as its radius. Assuming this we have the following:
Vs / Vc = 4πr³ / 3πr²h
Vs/Vc = 4πr³ / 3πr³
From here, we can cancel out the values of π and r³:
Vs/Vc = 4/3
<h2>
Vs = 4/3 Vc</h2>
Thus we can conclude that the volume of the sphere is 4/3 the volume of a cylinder.
Hope this helps
A) I believe but you might not want to go with it cause I'm not good at math AT ALL:)
75.7 I think that is the answer