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2 years ago

If f(x) = 56-2x, find f(7)

Mathematics

2 answers:

Lorico [155]2 years ago

3 0

Answer: 42

Step-by-step explanation:

Simply substitute 7 for x.

56 - 2(7)

56 - 14

Hope it helps <3

tensa zangetsu [6.8K]2 years ago

3 0

Answer:

f(7)=42

Step-by-step explanation:

f(x)=56-2x

Here put x=7

f(7)=56-2(7)

f(7)=56-14

f(7)=43

I hope this will help you :)

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a scale drawing of a building needs to be made using the scale 1 in = 190 ft. how tall will the builging in the scale drawing be

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Answer:

$\boxed{\text{3 in}}$

Step-by-step explanation:

1 in = 190 ft

x in = 570 ft

We can use ratio and proportion to solve this problem.

$\begin{array}{cccl}\dfrac{1}{x} & = & \dfrac{190}{570} & \\\\570 & = & 190x & \text{Mutiplied by lowest common denominator (570x)}\\3 & = & x & \text{Divided each side by 3}\\\end{array}$

The building will be $\boxed{\textbf{3 in}}$ tall in the scale drawing.

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2 years ago

Figure out this 16r^3t^2/-4rt

ElenaW [278]

You mean to simplify as this is an expression not an equation, as it has no equal sign...

Factor our 4 first

(4r^3t^2)/(-rt)

Now factor out -rt

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8 0

2 years ago

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Enter the missing numbers in the boxes to complete the table of equivalent ratios

son4ous [18]

Answer:

Time(min)

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Step-by-step explanation:

the time is 1/3rd of the distance. it's a 1:3 ratio

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3 years ago

The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

$\\$

To Find:

Curved surface area
Volume

$\\$

Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

<em>Substituting the required values: </em>

$\\$

$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

<em>Substituting the required values, </em>

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

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