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mojhsa [17]
3 years ago
15

What is 4/5 times 1/2 times 1/3

Mathematics
2 answers:
svetlana [45]3 years ago
5 0
The answer is 2/15!! Hope I helped
vovikov84 [41]3 years ago
4 0

Answer:

2/15

Step-by-step explanation:

Step 1: 4/5 x 1/2 = 2/5

Step 2: 2/5 x 1/3= 2/15


Hope this helped!


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Part A: 6m + 12 + 42m, which combines to form 48m + 12. Another expression is 12 + 48m, because using the commutative property of addition, it is equivalent.

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Part C: If you substitute 2 for m, you will get 108. If they are talking about the main equation, then if you substitute 2 for m, you will have 6(2 + 2 + 14) = 108.
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someone solve this question for me with detailed explanation and step by step so i can grasp the concept
natta225 [31]

Answer:

3rd grade

Step-by-step explanation:

Given that the values are different types (fractions, decimals, and percentages), it would be helpful to convert them to the same type of value.

Converting everything to percentages seems more convenient.

Since 61.24% is already a percentage, we simply have to convert 0.52, 25/36, and 0.5274444 (I wrote 0.5274 like this since the 4 is a repeating value).

To convert 0.52, we simply multiply by 100:

0.52 * 100 = 52%

For 25/36, we need to know its decimal form and multiply by 100 to find the percentage:

25 / 36 = 0.6944 * 100 = 69.44%

For 0.5274444, we also multiply by 100:

0.5274444 * 100 = 52.74444

Thus, we have 52% (2nd grade), 69.44% (3rd grade), 61.24% (4th grade), and 52.74444% (5th grade).

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3 0
2 years ago
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
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