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KengaRu [80]
3 years ago
8

Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minut

es. How many pages does the task contain if printer B prints 5 pages a minute more than printer A ?
1: 600
2: 800
3: 1000
4: 1200
5: 1500
Computers and Technology
1 answer:
sasho [114]3 years ago
7 0

Answer:

The correct answer to this question is option (1).

Explanation:

Let x1 = Is number of pages that printer A can print  in page/minute.  

thus x1 + 5 = Is number of page that printer B can print in page/minute.  

As printer A finishes his work in 60 min. So the task has 60x1 pages. As printers A and B both finish that task in 24 minutes. So the equation can be given as:  

60x1 = 24x1 + 24(x1 + 5)  

 

60x1 = 24x1 + 24x1 + 120  

 

60x1=48x1 + 120

 

60x1-48x1=120

 

12x1=120  

 

x1=120/12

 

x1=10

put the value of x1 in to (60x1). Therefore, the task has 60(10) = 600 pages. the task contains 600 pages.  

So the answer to this question is option (1).

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Answer:

This solution is implemented in C++

void makePositive(int arr[]){

   int i =0;

   while(arr[i]!=0){

       if(arr[i]<0){

           arr[i] = abs(arr[i]);

       }

       i++;

   }

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Explanation:

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void makePositive(int arr[]){

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   int i =0;

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   while(arr[i]!=0){

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<em>    while(arr[i]!=0){ </em>

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<em>     i++; </em>

<em> }   </em>

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See attachment for full program which includes the main

Download cpp
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