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3 years ago

The difference between

" alt=" \sqrt[2]{72} " align="absmiddle" class="latex-formula"> and $\sqrt{8}$ is
A) $\sqrt[10]{2}$
B) $\sqrt[8]{2}$
C) $\sqrt[6]{2}$
D) $\sqrt{2}$

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

$\sqrt{72}-\sqrt{8}=\sqrt{36\cdot 2}-\sqrt{4\cdot 2}\\\\=6\sqrt{2}-2\sqrt{2}=4\sqrt{2}$

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A bakery makes 260 donuts in 4 hours. At this rate, how many donuts can they make in 6 hours?

RSB [31]

Answer:

390

Step-by-step explanation:

8 0

3 years ago

State whether the lines are parallel, perpendicular,or neither.

cluponka [151]

Answer:

Please check the explanation.

Step-by-step explanation:

Two lines are parallel if their slopes are equal.

Two lines are perpendicular if the product of their slope is -1

We also know that the slope-intercept form of the line equation is

$y=mx+b$

where m is the slope and b is the y-intercept

Given the lines

y = 6х - 3

Comparing with y=mx+b, the slope of y = 6х - 3:

m₁=6

y = - 1/6x + 7

Comparing with y=mx+b, the slope of y = - 1/6x + 7:

m₂=-1/6

m₁ × m₂ = -1

6 × - 1/6 = -1

-1 = -1

Thus, the lines y = 6х - 3 and y = - 1/6x + 7 are perpendicular.

y = 3x + 2

Comparing with y=mx+b, the slope of y = 3x + 2:

m₁=3

2y = 6x - 6

simplifying to write in slope-intercept form

y=3x-3

Comparing with y=mx+b, the slope of y=3x-3:

m₂=3

As the slopes of y = 3x + 2 and 2y = 6x - 6 are equal.

i.e. m₁ = m₂ → 3 = 3

Thus, the lines y = 3x + 2 and 2y = 6x - 6 are paralle.

8x - 2y = 3

simplifying to write in slope-intercept form

y = 4x - 3/2

Comparing with y=mx+b, the slope of y = 4x - 3/2:

m₁=4

x + 4y = - 1

simplifying to write in slope-intercept form

y=-1/4x-1/4

Comparing with y=mx+b, the slope of y=-1/4x-1/4:

m₂=-1/4

m₁ × m₂ = -1

4 × - 1/4 = -1

-1 = -1

Thus, the lines 8x - 2y = 3 and x + 4y = - 1 are perpendicular.

3x+2y = 5

simplifying to write in slope-intercept form

y = -3/2x + 5/2

Comparing with y=mx+b, the slope of y = -3/2x + 5/2:

m₁=-3/2

3y + 2x = - 3

simplifying to write in slope-intercept form

y = -2/3x - 1

Comparing with y=mx+b, the slope of y = -2/3x - 1:

m₂=-2/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

y - 5 = 6x

simplifying to write in slope-intercept form

y=6x+5

Comparing with y=mx+b, the slope of y=6x+5:

m₁=6

y - 6x = - 1

simplifying to write in slope-intercept form

y=6x-1

Comparing with y=mx+b, the slope of y=6x-1:

m₂=6

As the slopes of y - 5 = 6x and y - 6x = -1 are equal.

i.e. m₁ = m₂ → 6 = 6

Thus, the lines y - 5 = 6x and y - 6x = -1 are paralle.

y = 3х + 9

Comparing with y=mx+b, the slope of y = 3х + 9:

m₁=3

y = -1/3x - 4

Comparing with y=mx+b, the slope of y = 1/3x - 4:

m₂=1/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

8 0

2 years ago

How would you solve that problem

antiseptic1488 [7]

Since you that that line is 180 degrees you can simply do 180-149 and find that the answer is 31 degrees. So you would do 13x+5=31, 31-5=26, 26/13, and then x=2 :)

7 0

3 years ago

Plz answer will mark brainliest

LUCKY_DIMON [66]

Answer:

(5.5, 6)

Step-by-step explanation:

Find the difference between them and then divide by 2 and add to one point

7 0

3 years ago

5. Find the lateral surface area of the net of the cube. 1.8 cm

igor_vitrenko [27]

Given:

Given that the side length of the cube is 1.8 cm

We need to determine the lateral surface area of the cube.

Lateral surface area of the cube:

The lateral surface area of the cube can be determined using the formula,

$LSA=4a^2$

where a is the side length.

Substituting a = 1.8 in the above formula, we get;

$LSA=4(1.8)^2$

Squaring the term, we get;

$LSA=4(3.24)$

Multiplying, we get;

$LSA=12.96$

Thus, the lateral surface area of the cube is 12.96 cm²

6 0

3 years ago