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cestrela7 [59]
3 years ago
6

You and your friend are having a race, but since you are faster than him, you decide to give him a head start. He starts 10m in

front of the starting line while you start on the starting line. You run at 6 meters/second, while your friend runs at 5.5 meters/second. After how many seconds will you and your friend be same distance from the starting line? seconds months
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

20 seconds

Step-by-step explanation:

Your friend starts 10 meters in front of the starting line.

You start from the starting line.

You run at 6 meters/ second.

Your friend runs at 5.5 meters/second.

You and your friend will be at the same distance from the starting line only when you are able to catch your friend.

The relative speed between you two is the difference in your speed and your friend's speed that is:

6-5.5=0.5m/s

So to cover 10 meters of separation at the speed of 0.5 meter/second it will take:

t=\frac{10}{0.5}= \frac{100}{5}=20s

So it will take 20 seconds for you and your friend to be at the same distance from the starting line.  

yanalaym [24]3 years ago
5 0

Answer:

20 seconds is correct.

Step-by-step explanation:

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2 years ago
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3. A soccer team played 160 games and won 65 percent of them. How many games did the team win?
Airida [17]

Answer:

b.) 104

Step-by-step explanation:

Percent formula:

x/y = p/100

where x is the fraction, y is the total, and p is the percent

This means:

x = number of games the team won

y = total number of games

p = percent the number of teams won

Let's plug these values into the equation:

x/y = p/100

x/160 = 65/100

Solve by cross-multiplying:

x/160 = 65/100

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100x = 10,400

/100     /100

x = 104

Therefore, the team won 104 games.

6 0
2 years ago
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Goryan [66]
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4 0
3 years ago
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wariber [46]

Answer:

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Step-by-step explanation:

8 0
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