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Neko [114]
3 years ago
6

The law of cosines reduces to the Pythagorean theorem whenever the triangle is acute. true or false

Mathematics
2 answers:
inysia [295]3 years ago
6 0
False- the included angle must be a right angle for cos C to be 0 & two other points are normally used
Sholpan [36]3 years ago
3 0

Answer:

The given statement is False.

Step-by-step explanation:

Let us suppose a triangle ABC.

The law of cosine is given by

c^2=a^2+b^2-2ab\cos C

And the Pythagorean theorem is given by

c^2=a^2+b^2

Now, in order to the law of cosine to be in the form of Pythagorean theorem, we must have 2abcos C =0.

a and b can't be zero since it represent the sides of the triangle. Hence, we have

cos C= 0

thus, the value of C is 90 degrees. Hence, the triangle must be a right angle triangle.

Thus, the triangle shouldn't be acute triangle.

Therefore, the given statement is false/

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Answer:

1. 35

2. 145

3. 55

4. 90

5. 145

Step-by-step explanation:

1. 35: angle 1 and 2 are a linear pair (meaning it is in one line and adds to 180). Since we know angle 2 is 145, ∠1 = 180 - 145

∠1 = 35

2. 145: ∠7 = ∠2 because they are alternate angles and alternate angles are equal

3. 55: ∠7 = ∠5 + ∠4 because vertically opposite angles are equal. We know that ∠5 = 90, hence ∠4 would equal 145 - 90 = 55

4. ∠5 = 90. It is given

5. 145: ∠9 = ∠2 because they are vertically opposite

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2. Alicia is writing the program for a video game. For one part of the game she uses the rule to move points on the screen.
Gwar [14]

<em>Complete Question:</em>

<em>Alicia is writing the program for a video game. For one part of the game she uses the rule (x,y)->(x-3,y+4) to move points on the screen. </em>

<em>A) what output does the rule give when the input is (-6,0)? </em>

<em>B)What output does the rule give when the input is (3,-4)? </em>

<em>C) Is the rule a function? Explain why it is or why it is not </em>

Answer:

a. The output is (-9,4)

b. The output is (0,0)

c. See Explanation

Step-by-step explanation:

Given

Rule: (x,y)->(x - 3, y + 4)

Solving (a):

Inputs:

x = -6

y = 0

The outputs is as follows;

x => x - 3

x => -6 - 3

x => -9

y=> y + 4

y=> 0 + 4

y=> 4

Hence:

The output is (-9,4)

Solving (b):

Inputs:

x = 3

y = -4

The outputs is as follows;

x => x - 3

x=>3-3

x = 0

y=> y + 4

y=>-4+4

y=>0

Hence:

The output is (0,0)

Solving (c):

The function is a rule and the rule is that:

It shifts the graph left by 3 units and up by 4 units

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