Answer:
5/22 or 0.22%
Step-by-step explanation:
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Answer:
Adults= 110
Children= 340
Step-by-step explanation:
Given data
let adults be x
and children be y
x+y= 450----------1
2x+y=680---------2
from 1
x= 450-y
put this in 2
2(450-y)=680
900-2y=680
900-680=2y
220=2y
y= 220/2
y= 110
x+110= 450
x= 450-110
x=340
X = nr. hrs working for a farmer;
y = nr. hrs. babysitting;
x + y <= 25;
10x + 5y >= 150
a) Solve the system => one of the solution is x =5; y = 20(babysitting)
b) 10 + 12 =22 <= 25; 10*10 + 5*12 = 160 >=150.
