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Natalka [10]
3 years ago
8

Given sample set A= {1,2,3,4,5} how many items are in the complement of set B if set B= all numbers greater than 2? OPTIONS : 3

, 5, 2 , or 4
Just stuck on this one question.
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
6 0

Answer:

2

Step-by-step explanation:

It sounds like we are pretending A is the universe.  The only numbers in our world are 1,2,3,4, and 5.

You are given B is all numbers greater than 2.

The complement of B would all the elements not listed in B.

The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.

The elements not in B are 1 and 2.

So B complement is {1,2}.

There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.

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Answer:

(-7,4) and (-9,7)

Step-by-step explanation:

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Evaluate |16 + (-9) +2|
Aleks [24]
16 + (-9) + 2 = 9 Well sixteen plus negative nine plus two is equaled out to be positive nine. 
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What is the answer to <br>-8(-6x +7)&lt;-440
timama [110]

Hello there!

<u><em>Answer: ⇒⇒⇒⇒⇒ x</em></u>

_____________________________________________________________

Step-by-step explanation:

First you had to divide by 8 from both sides of equation.

\frac{-8(-6x+7)}{8}

Simplify.

6x-7

Then you had to add by 7 from both sides of equation.

6x-7+7

Simplify.

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Divide by 6 from both sides of equation.

\frac{6x}{6}

Simplify it should be the correct answer.

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3 years ago
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Question Progress
andreyandreev [35.5K]

The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

Step-by-step explanation:

The given is,

                  The sum of two numbers is 21

                   The second number is six times the first number

Step:1

          Let, m - First number

                  n - Second number

Step:2

        From given,

                  n - 6m     ( The second number is six times the first number )

        Equation becomes,

                  Sum = m + n

        Where,

                      21 = m + ( 6m )

                       21 = 7m

                       m = 3

        Substitute m value n becomes,

                        n = 6m

                           = (6 × 3)

                      n  = 18

Result:

          The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

                   

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Answer:

4

Step-by-step explanation:

2-(-2)=2+2=4

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