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kow [346]
3 years ago
8

Y = x2 - 2x + 1 Solve the equation algebraically

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Just factor. y = (x-1)(x-1)

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Evaluate each function.<br> 15) f(n)= n° + 3n?; Find f(-4a²)
coldgirl [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
Solve and check: 3 x2 + 5x + 6 + x − 1 x + 2 = 7 x + 3
vagabundo [1.1K]

Answer:

3x^{2} -2x +5=0

Step-by-step explanation:

Combine liked terms:

3x^{2}+5x+x-1x+6+2=7x+3

3x^{2}+6x-1x+8=7x+3

3x^{2}+5x+8=7x+3

Subtract 3: 3x^{2}+5x+8-3=7x+3-3

3x^{2}+5x+5=7x

Now subtract 7x:

3x^{2}+5x+5-7x=7x-7x

If you want combine liked terms:

3x^{2}-7x+5x+5=0

3x^{2}-2x+5=0

Hope this helps!

5 0
3 years ago
Please help me with this AP Calculus question!!
Temka [501]

9514 1404 393

Answer:

  B.  3

Step-by-step explanation:

If all you want is a numerical result, sometimes a graphing calculator can provide that easily. The attachment shows it calculates the slope at x=4 to be 3.

  dy/dx = 3 at x = 4

__

The derivative of the expression can be found from the quotient formula:

  d(u/v) = (du·v -u·dv)/v²

  y' = ((x -2)(2x -7) -(x^2 -7x +2)(1))/(x -2)^2

  = (2x^2 -11x +14 -x^2 +7x -2)/(x -2)^2

  = (x^2 -4x +12)/(x -2)^2

  = ((x -4)x +12)/(x -2)^2

Then for x=4, we have ...

  y' = 12/4 = 3

  dy/dx = 3 at x = 4

7 0
3 years ago
NEED HELP ASAP!!
Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

F =G\times \dfrac{M \cdot m}{r^{2}}

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2}  = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx  1.14

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

6 0
3 years ago
A random sample of 18 adults, chosen from the 1500 adults in the town, took a survey asking their opinion on a recent property t
Tamiku [17]

Answer:

C) I & III

Step-by-step explanation:

Given:

Sample size, n = 18

Sample proportion = 25% = 0.25

Here, a random sample of 18 adults were chosen from the 1500 adults in town. This shows that the random condition was satisfied because the sample was drawn randomly from the general population of adults in the town.

For the normal condition to be satisfied, np should be greater than 10, ie np > 10.

In this case, np = 18 * 0.25 = 4.5

Since np is less than 10, the normal condition was not satisfied.

For the 10% condition to be satisfied, sample size should not be more than 10% of the general population.

Here, the sample size is 18 and the population is 1500. Therefore,

\frac{18}{1500} * 100 = 1.2

Since the sample size is 1.2% of the population which is less than 10%, the 10% condition was satisfied.

The correct option is C, because only I & III were satisfied.

4 0
3 years ago
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