Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC . AD=8x−15AD=8x−15 and DC=57DC=57 .
2 answers:
AD=8x−15, <span>DC=57
</span><span>BD is a perpendicular bisector of segment ACsegment
so
AD = DC
8x - 15 = 57
8x = 57 +15
8x = 72
x =72/8
x =9</span>
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