3 years ago

Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC . AD=8x−15AD=8x−15 and DC=57DC=57 .

2 answers:

8 0

AD=8x−15, DC=57

BD is a perpendicular bisector of segment ACsegment
so
AD = DC
8x - 15 = 57
8x = 57 +15
8x = 72
x =72/8
x =9

Charra [1.4K]3 years ago

7 0

I hope this helps you

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