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3 years ago

Find a model for the set of values Plz help ASAP

Mathematics

1 answer:

Ahat [919]3 years ago

6 0

Answer:

none of the above

Step-by-step explanation:

No graph matches the table.

Have your teacher show you how you're supposed to work this problem and choose an answer (and check it).

_____

The parabola opening upward (graph 2) may be the closest, but it has points (±2, 0), not (±2, 4).

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4 years ago

The sum of a number times 6 and 16 is greater than 22

Zanzabum

Answer:

Any number above 1

Step-by-step explanation:

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3 years ago

a furniture store is having a weekend sale and is offering a 20% discount on patio chairs and tables.the sales tax on furniture

Yuliya22 [10]

A = x(0.2) + 6.25x I believe

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4 years ago

A closed box with a square base is to have a volume of 171 comma 500 cm cubed. The material for the top and bottom of the box co

Zepler [3.9K]

Answer:

$C(x)=\dfrac{20x^3+1715000}{x}\\$Minimum cost, C(35)=\$29,400$

The dimensions that will lead to minimum cost of the box are a base length of 35 cm and a height of 140 cm.

Step-by-step explanation:

Volume of the Square-Based box=171,500 cubic cm

Let the length of a side of the base=x cm

Volume $=x^2h$

$x^2h=171,500\\h=\dfrac{171500}{x^2}$

The material for the top and bottom of the box costs $10.00 per square centimeter.

Surface Area of the Top and Bottom $=2x^2$

Therefore, Cost of the Top and Bottom $=\$10X2x^2=20x^2$

The material for the sides costs $2.50 per square centimeter.

Surface Area of the Sides=4xh

Cost of the sides=$2.50 X 4xh =10xh

$\text{Substitute h}$=\dfrac{171500}{x^2} $into 10xh\\Cost of the sides=10x(\dfrac{171500}{x^2})=\dfrac{1715000}{x}$

Therefore, total Cost of the box

$= 20x^2+\dfrac{1715000}{x}\\C(x)=\dfrac{20x^3+1715000}{x}$

To find the minimum total cost, we solve for the critical points of C(x). This is obtained by equating its derivative to zero and solving for x.

$C'(x)=\dfrac{40x^3-1715000}{x^2}\\\dfrac{40x^3-1715000}{x^2}=0\\40x^3-1715000=0\\40x^3=1715000\\x^3=1715000\div 40\\x^3=42875\\x=\sqrt[3]{42875}=35$

Recall that:

$h=\dfrac{171500}{x^2}\\Therefore:\\h=\dfrac{171500}{35^2}=140cm$

The dimensions that will lead to minimum costs are base length of 35cm and height of 140cm.

Therefore, the minimum total cost, at x=35cm

$C(35)=\dfrac{20(35)^3+1715000}{35}=\$29,400$

8 0

3 years ago

Find the volume of the Grain silo show below that has a diameter of 20ft and a height of 50ft

Aleks [24]

$Volume=Area_{base}*height\\\\
Volume= \pi radius^2*height\\\\
diameter=2radius\\
radius=10ft\\\\
Area= \pi 10^2*50=5000 \pi ft^3\\\\
Volume\ of\ Grain\ silo\ is\ 5000 \pi ft^3.$

3 0

4 years ago