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2 years ago

Consider the equation below. log4 (x+3)=log2 (2+x). Which system of equations can represent the equation?

Mathematics

2 answers:

Verdich [7]2 years ago

4 0

Using: loga b = log b / log a
1) a=x+3, b=4 → y1=log4 (x+3) → y1= log (x+3) / log 4
2) a=2+x, b=2 →y2=log2 (2+x) → y2=log (2+x) / log 2

Answer:
y1=log (x+3) / log 4, y2= log (2+x) / log 2

klio [65]2 years ago

3 0

answer is attached below

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3/16=(-5/4)+g please help me

Alla [95]

Answer:

g= $\frac{23}{16}$

Step-by-step explanation:

To begin you want to isolate the g. So you add $\frac{5}{4}$ to both sides. On the left is cancels out so it looks like this:

$\frac{3}{16} +\frac{5}{4} =g$

Next, you find the Least Common Denominator (LCD) which is 16. And since one fraction already has a denominator of 16 you leave it as it is. The other fraction, however, needs to be multiplied (both top and bottom) by 4 to get the denominator (bottom) to 16. So:

$\frac{3}{16} +(\frac{5}{4}*\frac{4}{4} ) =g$

Multiplying it out you get:

$\frac{3}{16} +\frac{20}{16} =g$

Lastly, just add across:

$\frac{3+20}{16} =\frac{23}{16}$

You're done!

$g=\frac{23}{16}$

6 0

2 years ago

And I college library there are four times as many non-fiction books as fiction books.

Lynna [10]

A is 1:4, b is 4 times, and c is 7:9

3 0

3 years ago

Solve: Factor the following polynomial completely -9x^2-30x-25

Korolek [52]

Answer:

(−3x−5)(3x+5)

Step-by-step explanation:

−9x2−30x−25

=(−3x−5)(3x+5)

3 0

3 years ago

Read 2 more answers

What is the total surface area of the drawing?

kkurt [141]

The answer will be 21.2kilometers

7 0

3 years ago

-x=-y+2 and 3y+4=2x solve using matrices

MissTica

$\begin{cases}-x=-y+2\\3y+4=2x\end{cases}\implies\begin{cases}x-y=-2\\2x-3y=4\end{cases}$

In matrix form, this is

$\begin{bmatrix}1&-1\\2&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-2\\4\end{bmatrix}$

The coefficient matrix has determinant

$\begin{vmatrix}1&-1\\2&-3\end{vmatrix}=-3+2=-1\neq0$

so it has an inverse, which is

$\begin{bmatrix}1&-1\\2&-3\end{bmatrix}^{-1}=\begin{bmatrix}3&-1\\2&-1\end{bmatrix}$

Multiply both sides by the inverse matrix:

$\begin{bmatrix}3&-1\\2&-1\end{bmatrix}\begin{bmatrix}1&-1\\2&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}3&-1\\2&-1\end{bmatrix}\begin{bmatrix}-2\\4\end{bmatrix}$

$\implies\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-10\\-8\end{bmatrix}$

so that $x=-10$ and $y=-8$ .

8 0

3 years ago