Answer:
C) a = 432
Step-by-step explanation:
Answer:
see the explanation
Step-by-step explanation:
we know that
An equilateral triangle has three equal sides and three equal interior angles.
The measure of each interior angle is 60 degree
see the attached figure to better understand the problem
Let
b ----> the length side of the triangle
In the right triangle ABD
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
solve for b
Remember that
substitute
simplify
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
The second number of each ordered pair for g(x) is 2 less than that for f(x).
The value of k is -2.