Please help math homework to hard

Charles owns a catering business. The amount his 10 most recent clients spent is shown in the histogram below. Why is the graph

Alexxandr [17]

<span>The scales are different on the x-axis and the y-axis.
</span>Therefore, the correct answer choice is:
A. The x-axis scale shows the data is more clustered than it actually is.

5 0

3 years ago

Read 2 more answers

What is the answer to this

LekaFEV [45]

$4 \dfrac{3}{5} \times \dfrac{5}{12} =$

$= \dfrac{23}{5} \times \dfrac{5}{12}$

You changed the mixed numeral into a fraction correctly.
Now you need to multiply the fractions.
Multiply the numerators together, and multiply the denominators together.

$= \dfrac{23 \times 5}{5 \times 12}$

Now we could multiply out the numerator and denominator, and then we'd need to reduce the fraction, but before we multiply, we see there is a factor of 5 both in the numerator and in the denominator, so we can reduce before we multiply.

$= \dfrac{23 \times 5}{12 \times 5}$

$= \dfrac{23}{12}$

$= 1 \dfrac{11}{12}$

6 0

3 years ago

Suppose that for a randomly selected high school student who has taken a college entrance exam, the probability of scoring above

Sophie [7]

Answer:

3.0

Step-by-step explanation:

n=10

p=0.30

mean=np=10X0.3 = 3

That is it.

5 0

3 years ago

A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline

dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So $P(B) = 0.35$

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

$P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125$

Probability

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667$

46.67% probability that they flew with airline B.

5 0

3 years ago

What is the y-intercept of this quadratic?

MAVERICK [17]

Answer:

(0,8)

Step-by-step explanation:

The line crosses the y axis at (0,8)

8 0

3 years ago