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Sliva [168]
4 years ago
11

What’s the linear equation for -4x-y=-4

Mathematics
2 answers:
stepladder [879]4 years ago
8 0
Add the y add the righmost 4 and reaarange
eduard4 years ago
8 0
The linear equation is y=4x-4 plug it in a calculator and you see the graph and answer
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In a bag, there are 5 cards numbered 1 to 5. Each time a card is randomly selected, it I'd replaced in the bag. What is the prob
sweet [91]

Out of 5 cards in the bag ...

-- There are 2 even numbers . . . 2 and 4 .

-- There are 3 odd numbers . . . 1, 3, and 5 .

So EITHER time, the probability of pulling an even number is  2/5 ,
and the probability of pulling an odd number is  3/5 .

The probability of pulling an even number the first time
AND an odd number the second time is

       (2/5) x (3/5)  =  6/25  =  <em>24%</em> .

 
3 0
3 years ago
Read 2 more answers
Each year a store decreased the price of certain model of TV by $35.If the price in 2001 was $1,950,what was the price in 2009?
Vanyuwa [196]
The answer is 1,670 because you have to multiply 35*8 which equals 280 and subtract it from 1950, and you get 1,670.
7 0
4 years ago
All of them plzzzzzzzzzzzzz
vladimir1956 [14]
The diamond is parallels
8 0
3 years ago
Which of these scales are equivalent to 3 cm to 4 km?
satela [25.4K]

Answer: The answer is A and D

3 0
3 years ago
What are the potential solutions to the equation 2ln(x+3)=0
skad [1K]
2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1

Expanding the left side gives

x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0

which gives two solutions, x=-4 and x=-2. But if x=-4, then \ln(x+3)=\ln(-1), but this number isn't real, so x=-4 is an extraneous solution. Meanwhile if x=-2, you get \ln(-2+3)=\ln1=0, so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
4 0
4 years ago
Read 2 more answers
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