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3 years ago

Evaluate each expression below.1. 7-2(x-4) when x = 5

Mathematics

1 answer:

Ivahew [28]3 years ago

7 0

Answer:

Step-by-step explanation:

7-2(x-4) when x = 5

7-2(5-4)= 7-2(1)= 5

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Step-by-step explanation:

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Find the value of the determinant using the method of expansion by minors; expand on the third row

valkas [14]

For the matrix

$\begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}$

the determinant using the method of expansion by minors, expanding on the third row is:

$\det \begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}=a_{31}\det \begin{bmatrix}{a_{12}} & {a_{13}} & {} \\ {a_{22}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}-a_{32}\det \begin{bmatrix}{a_{11}} & {a_{13}} & {} \\ {a_{21}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}+a_{33}\det \begin{bmatrix}{a_{12}} & {a_{12}} & {} \\ {a_{22}} & {a_{22}} & {} \\ {} & {} & {}\end{bmatrix}$

Answer:

First, we compute the determinants of the minors:

$\begin{gathered} \det \begin{bmatrix}{0} & {4} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=0+4=4, \\ \det \begin{bmatrix}{1} & {4} & {} \\ {1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=3-4=-1, \\ \det \begin{bmatrix}{1} & {0} & {} \\ {1} & {-1} & {} \\ {} & {} & {}\end{bmatrix}=-1-0=-1. \end{gathered}$

Therefore:

$\det \begin{bmatrix}{1} & {0} & {4} \\ {1} & {-1} & {3} \\ {0} & {5} & {-2}\end{bmatrix}=0\times4-5\times(-1)+(-2)\times(-1)=5+2=7.$

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1 year ago

What is the interest earned on $620 at a rate of 3% for one year. Please help!

natima [27]

Answer:

$18.6 interest

Step-by-step explanation:

3% of 620=

(3x620)/100=18.6

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3 years ago

The depth y (in inches) of a lake after x years is represented by the equation y=0.2x+42 . How much does the depth of the lake i

blagie [28]

Answer:

Step-by-step explanation:

Step one:

given data

we are told that the expression for the depth of a lake after x years is given by

$y=0.2x+42$

Required

The value of y when x= 4

Step two:

substitute the value of x in the expression to get y

$y=0.2(4)+42\\\\y=0.8+42\\\\y=42.8\\\\$

<em><u>After 4 years the depth will increase by 42.8 in</u></em>

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3 years ago

Evaluate each expression below.1. 7-2(x-4) when x = 5​

Evaluate each expression below.1. 7-2(x-4) when x = 5