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3 years ago

Find the distance between 2-3i and 9+21i

Mathematics

1 answer:

Andre45 [30]3 years ago

6 0

Answer:

Step-by-step explanation:

The distance is the magnitude of the difference:

|(2 -3i) -(9 +21i)| = |-7 +24i| = √((-7)² +24²) = √625 = 25

The distance between the two points in the complex plane is 25 units.

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5 is 5% of what number?

iragen [17]

Answer:

100

Step-by-step explanation:

8 0

3 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago

Plz help with this question

Nesterboy [21]

debt is greater than 25

you owe more than 25 dollars

6 0

2 years ago

Please help, what is the value of x

marusya05 [52]

I think the answer is x=2 <span />

6 0

3 years ago

Can someone help me please?

jeka57 [31]

Answer:

Step-by-step explanation:

because A is half of that and if you divided 170 by 2 you would get 85, I think that's how you do it.

7 0

3 years ago