All categories

3 years ago

Write equation and solve.

Mathematics

2 answers:

Mumz [18]3 years ago

8 0

46
Take 15 away from 38
=23
Then you double that
=46

elena-14-01-66 [18.8K]3 years ago

4 0

(38 - 15) * 2 = c

c = original cards.

38 - 15 = 23

23 * 2 = 46

You started with 46 cards.

38 - 15 represents subtracting the cards you bought from the half of your original cards.

The * 2 represents multiplying the number of cards you had (without the new ones you bought) being multiplied by 2 (because you lost half of them).

You might be interested in

Mr. Mayntz's math class is made up of 29 students. Some of the students are male

zaharov [31]

Answer:

Statements 2 and 3.

Step-by-step explanation:

The first statement is impossible since you cannot have half a person. The last statement is also incorrect, because it would imply that the total number of students in the class is -29. The second statement is correct, if you assume that x and y represent either the number of male or female students. The third statement is possible, and the numbers add up to 29. Finally, the fourth statement is impossible because it would imply that the class had negative male students. Hope this helps!

5 0

3 years ago

Suppose you are going to conduct a two tail test concerning the population mean. Suppose that you do not know what the populatio

IRINA_888 [86]

Answer:

The critical value of t at 0.01 level of significance is 2.66.

Step-by-step explanation:

The hypothesis for the two-tailed population mean can be defined as:

H₀: μ = μ₀ vs. H₀: μ ≠ μ₀

It is provided that the population standard deviation is not known.

Since there is no information about the population standard deviation, we will use a t-test for single mean.

The test statistic is defined as follows:

$t_{cal.}=\frac{\bar x-\mu}{s/\sqrt{n}}\sim t_{\alpha/2, (n-1)}$

The information given is:

n = 55

α = 0.01

Compute the critical value of t as follows:

$t_{\alpha/2, (n-1)}= t_{0.01/2, (55-1)}=t_{0.005, 54}=2.66$

*Use a t-table for the value.

If the desired degrees of freedom are not provided consider he next highest degree of freedom.

Thus, the critical value of t at 0.01 level of significance is 2.66.

4 0

3 years ago

What is 5 3/8 as a inproper fracon and as a mixed number

ICE Princess25 [194]

$\frac{53}{8}$
To divide 53 by 8 wont be possible so u find a number that when you multiply by 8 it gives u a number closer to 58 which is 8*6=48 i.e 53 divided by 8 is 6 rem, then to get the reminder you subtract 42 from 53 i.e 53–48=5 so the final answer will be 6 and 5/6

3 0

3 years ago

Oblicz granicę ciągu (pierwiastek z (n^2+6)/2n+2).

kap26 [50]

Answer:

umm what

Step-by-step explanation:

6 0

4 years ago

Based only on the information given in the diagram, which congruence

romanna [79]

<h3>1 Answer: Choice D) SAS</h3>

=================================================

Explanation:

LA stands for Leg Angle. More specifically, the angle is an acute angle. This theorem only works for right triangles. We see that ED = LK which is one pair of congruent leg segments. So that takes care of the L part of LA. However, we don't know anything about the acute angles. We don't know if angle E = angle L, or if angle F = angle M, or something along those lines. We need angle markers to tell us or not.

In short, we only have half the info needed for LA, so we must cross choice A off the list.

----------------

HA stands for hypotenuse angle, or hypotenuse acute angle, and this rule only applies for right triangles. We don't know anything about the hypotenuse lengths if they are the same or not.

Similar to choice A, we don't know anything about the acute angles either.

Those two facts mean we must cross off choice B.

----------------

AAS stands for Angle Angle Side. The order is important because the side is not between the angles. The diagram only shows one pair of angles that are congruent to one another. That pair being the 90 degree angles indicated with the square marker. We don't have another pair of angles, so we cannot use AAS.

Cross choice C off the list.

-----------------

We can use SAS because we have two pairs of congruent sides and one pair of congruent angles.

The congruent sides are

ED = LK (double tickmarks)
DF = KM (single tickmarks)

That takes care of the two "S"s of "SAS". The "A" would be those two right angles which are congruent to one another. The angles are between the congruent sides which is important. Recall that SSA is not a valid congruence theorem.

So that's why choice D is the only answer.

-----------------

Side note: We could use the LL theorem, where L stands for leg, since we are given two pairs of congruent legs for each triangle. Like LA and HA, this only applies to right triangles. LL is a special case of SAS. However, LL isn't listed so we'll just be sticking with SAS as the only answer.

8 0

3 years ago