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hodyreva [135]
3 years ago
7

What is the area of the triangle?

Mathematics
1 answer:
disa [49]3 years ago
5 0
Hello I am sorry to say this but no one can help you because you didn't put a picture of the triangle on.
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Rewrite the following in the form log(c). log(4) - log(2)
Elis [28]

Answer:

log(2)

Step-by-step explanation:

log(4) − log(2)

log(4/2)

log(2)

3 0
3 years ago
The difference between 9/5 and 7/5 is
Agata [3.3K]

Answer:

2/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Calculate the amount and the compound interest on Rs 12.000 in 2 years at 10%
mel-nik [20]

Answer:

Amount = p( 1+r/100) ^n

= 12000 ( 1+10/100) ²

= 12000( 10/10+1/10) ²

= 12000( 11/10) ²

= 12000 x 11/10 x 11/10

= 14520 rs.

Compund interest = amount - principal

= 14520 - 12000

= 2520rs.

Next question :- no of men can complete a piece of work in 7 days = 36

No of men can complete a piece of work in 42 day = ( 36 x 7 ) ÷ 42

= 252 ÷ 42

= 6 men

5 0
3 years ago
I need help...........​
bogdanovich [222]
Hello,

The answer is C, refer to this picture for an explanation.
Have a great day!!
Brainliest??

4 0
3 years ago
WILL mark brainliest!
Angelina_Jolie [31]

Answer:

  110.5348 minutes

Step-by-step explanation:

The difference from room temperature changes from 103 to 59 in 46 minutes, so that difference can be modeled by the exponential equation ...

  Δt = 103×(59/103)^(t/46)

We want to find t for the temperature difference Δt = 91 -64 = 27.

  27 = 103×(59/103)^(t/46)

  27/103 = (59/103)^(t/46) . . . . . divide by 103

Taking logs gives the linear equation ...

  log(27/103) = (t/46)log(59/103)

Multiplying by the inverse of the coefficient of t, we get ...

  t = 46·log(27/103)/log(59/103) ≈ 46·(-0.58147346)/(-0.24198521)

  ≈ 110.5347

It will take about 110.5347 minutes for the turkey to cool to 91 °F internally.

_____

<em>Comment on 4 decimal places</em>

An answer correct to 4 decimal places (7 significant digits) is a pretty good indication that the problem was worked correctly. However, that level of precision in the timing makes little sense in this context. Most thermometers will take at least a few seconds to register the temperature to within a tenth of a degree or so. This problem is asking for an answer that is within 6 milliseconds and 30 micro-degrees. Neither of these is anywhere near realistic for a kitchen meat thermometer.

More realistic would be an answer to 4 <em>significant figures</em>, a tenth of a minute and a few hundredths of a degree.

(The rate of change at the time of interest is about -0.33 degrees per minute.)

6 0
3 years ago
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