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netineya [11]
3 years ago
13

What's the new equation ?

Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0
H(x)=4(x-7)^2-16-3=4(x-7)^2-19\Rightarrow C
andrezito [222]3 years ago
4 0
4x^2-16  shift to right by 7 units by subtracting 7 from x...

4(x-7)^2-16  shift down by 3 units by subtracting 3 from the equation

4(x-7)^2-16-3

4(x-7)^2-19
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If the cost of those white tiles are $ 3.50 what is the unit cost per white
ryzh [129]

Answer:

how many tiles are "those" bc you cant figure it out without that info sorry.

Step-by-step explanation: y

7 0
3 years ago
A driver driving a business trip of 240 miles would have reached his destination if he'd been able to drive 12 mph faster than h
mariarad [96]

The average speed of his trip is = 12 mile/ hour

The total distance covered by the driver = 240 miles

The rate at which he traveled = 12 miles per hour

Therefore, the time he used to cover his distance

= 240/12

= 20 hrs

But average speed = distance/ time

= 240/ 20

= 12 miles/ hour

Therefore, the average speed of his trip is = 12 mile/ hour

Learn more here:

brainly.com/question/11753352

8 0
2 years ago
Hi so could anyone please tell me how to solve this I’ve tried looking through my notes but I can’t find a question similar to t
neonofarm [45]

Answer:

    no solution

Step-by-step explanation:

There are no values of x that make the equation true.

6 0
3 years ago
I am composed of only rectangular faces. I have 8 vertices. I am a solid figure.<br><br>what am I? ​
joja [24]

Answer:

the answer for your question is "It's a cuboid"

8 0
2 years ago
Read 2 more answers
If 150 grams of a radioactive isotope are present at 2:00 PM and 10 grams remain at 6:00 PM (the same day), what is the half-lif
pogonyaev

Initial amount, A_o=150\ g .

Final amount, A =10\ g .

Time taken, t = 6:00 - 2:00 = 4 hour.

We know,

A=A_o(\dfrac{1}{2})^{\dfrac{t}{h}}\\\\10 = 150 \times \dfrac{1}{2}^{\dfrac{4}{h}}\\\\2^{\dfrac{4}{h}}=15\\\\\dfrac{4}{h}= log_215\\\\h = \dfrac{4}{log_215}\\\\h = 1.024 \ hours

Therefore, the half-life of the isotope is 1.024 hours.

Hence, this is the required solution.

8 0
3 years ago
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