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Drupady [299]
3 years ago
12

Please help please please help

Mathematics
1 answer:
arsen [322]3 years ago
4 0
46.19 should be the answer
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I don't understand proportional relationship can u help? ​
Reptile [31]

Answer: I’ll explain it in simpler terms for you. A proportional relationship is one in which two quantities vary directly with each other. Ratios are proportional if they represent the same relationship. One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional. An example of a proportional relationship is simple interest, tax, markups and markdowns, gratuities and commissions, fees, percent increase and decrease, percent error. Hope this helps! :D

5 0
2 years ago
Find the slope . (5,8) and (-4,6) . can someone help plz
nadya68 [22]

An

2/9 is the answer

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Which statement is true about the x-intercepts?
N76 [4]

Answer:

The x-intercept is found by setting y = 0, because that will give us the x-value at which the line crosses the x-axis

Step-by-step explanation:

3 0
2 years ago
Find the value of x (3/5)^x(5/3)^2x=125/27​
lesya692 [45]

Given:

The equation is

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

To find:

The value of x.

Solution:

We have,

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

\left(\dfrac{5}{3}\right)^{-x}\left(\dfrac{5}{3}\right)^{2x}=\dfrac{5\times 5\times 5}{3\times 3\times 3}      [\because \left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^{m}]

\left(\dfrac{5}{3}\right)^{-x+2x}=\dfrac{5^3}{3^3}          [\because a^ma^n=a^{m+n}]

\left(\dfrac{5}{3}\right)^{x}=\left(\dfrac{5}{3}\right)^{3}

On comparing the exponents, we get

x=3

Therefore, the value of x is 3.

8 0
2 years ago
Diego was asked to plot these points: (−50,0) ( − 50 , 0 ) , (150,100) ( 150 , 100 ) , (200,−100) ( 200 , − 100 ) , (350,50) ( 3
Irina18 [472]

Answer:

We have the points:

(-50, 0)

(150, 100)

(200, -100)

(350, 50)

(-250, 0)

First, we need to find the smallest and largest values of the x-component.

The smallest value is x = -250

The largest value is x = 350

Then the interval that we choose for the x-axis should include these two values (so we can plot the points)

Then we need to use, at least, the interval [-250, 350]  (A interval that is a little bit larger than that will be easier to read, but that is the minimum he needs to do the plot)

Now let's do the same with the values of the y-components.

The smallest value is y = - 100

The largest value is y = 100

Then the vertical interval should be [-100, 100] or a little bit larger, like in the horizontal case.

We also can see that the values of x and y seem to jump in multiples of 50, then each unit of the grid could represent 50 units, so it is easier to plot. (These are also called intervals, and also theses will depend on each individual axis, but in this case we could use the same for both of them, because it works well for both axis)

4 0
3 years ago
Read 2 more answers
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